Purpose: To find out the percent yield of copper in the reaction between copper sulfate (CuSO4) and Iron (Fe). Materials: Balance 100-mL beaker 250-mL beaker Bunsen burner Copper sulfate crystals Glass stirring rod 100-mL graduated cylinder Iron filings Ring stand and ring Wire gauze Procedure: 1. Record mass of clean 100-mL beaker. 2. Add 8.0 grams of copper sulfate crystals to beaker. 3. Add 50.0 milliliters of distilled water to the crystals. 4. Put wire gauze on ring on ring stand, …showed first 75 words of 298 total…

…showed last 75 words of 298 total…copper<Tab/>2.54 g Percent yield of copper<Tab/>-17.32% Calculations: <Tab/>Actual yield of copper = 69.43 g - 67.33 g = 2.1 g Percent yield of copper = 2.1 g Cu - 2.54 g Cu <Tab/><Tab/><Tab/><Tab/><Tab/> 2.54 g Cu Conclusion: The percent yield of copper is -17.32%.